Math, asked by SwetaSweta11111, 1 year ago

if x+y=7/2 and xy=5/2 find (1)x-y (2) x^2-y^2

Answers

Answered by SravyaMaddula
4
hey here is your answer
hope u understand
Regards
Sravya Maddula
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SwetaSweta11111: correct answer
SravyaMaddula: hoo it sounds so nice
Answered by rlakhera38p8q1bb
0
firstly we construct a quadratic equation.
let \:  \alpha  +  \beta  =  \frac{7}{2}  \\ and \:  \alpha  \times  \beta  =  \frac{5}{2}  \\
we construct a quadratic equation which will be
 {x}^{2}  - (sum \: of \: roots)x + (product \: of \: roots)
 {x}^{2}  -  \frac{7}{2} x+   \frac{5}{2}  \\ and \: hence \: equation \: becomes \\ 2 {x}^{2}  - 7x + 5 \\
now let's come to our question
1)we \: know \: differrence \: of \: roots \: of \: quadratic \: equation \: is \:  =  \frac{ \sqrt{discriminnt} }{a}  \\
hence x-y = √49-40/2
which is equals to 3/2
now our second part
x^2-y^2=(x+y)(x-y)
=7/2*3/2
=21/4
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