if x+y=7 and x-y=1 then find the value of 8xy(x²+y²)
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Answer:
The value of 8xy(x²+y²) is 2400.
Step-by-step explanation:
8xy(x²+y²)
=4xy × 2(x²+y²)
={(x+y)²- (x-y)²} × {(x+y)² + (x-y)²} [According to formula]
=(7² -1²)(7²+1²)
=(49-1)(49+1)
=48 × 50
=2400(Ans)
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