Math, asked by ybhargavi50, 9 months ago

if x + y = 7 and xy = 2, then x² - y² = ?
(x > y)​

Answers

Answered by Anonymous
0

hey mate here is the answer

Using Identity : (a - b)² = a² + b² - 2ab

Using Identity : (a - b)² = a² + b² - 2ab(x - y)² = x² + y² - 2xy

Using Identity : (a - b)² = a² + b² - 2ab(x - y)² = x² + y² - 2xy⇒ 7² = x² + y² - 2(2)

Using Identity : (a - b)² = a² + b² - 2ab(x - y)² = x² + y² - 2xy⇒ 7² = x² + y² - 2(2)⇒ 49 = x² + y² - 4

Using Identity : (a - b)² = a² + b² - 2ab(x - y)² = x² + y² - 2xy⇒ 7² = x² + y² - 2(2)⇒ 49 = x² + y² - 4⇒ x² + y² = 49 + 4

Using Identity : (a - b)² = a² + b² - 2ab(x - y)² = x² + y² - 2xy⇒ 7² = x² + y² - 2(2)⇒ 49 = x² + y² - 4⇒ x² + y² = 49 + 4⇒ x² + y² = 53

hope it helps you

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Answered by sharmasangeeta2019
1

Answer:

I think your question is wrong.

Step-by-step explanation:

It should be

If x +y=7 and xy=2, then x^2 +y^2 is..

Hope you will consider.. Check the question once again and I will try to solve.

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