Question

If (x+y) = 7, xy = 12 Find x² + y².​

Answer 1

Answer:

$\huge\bf\underline\green{AnSweR:}$

$( {x + y})^{2} = {x}^{2} + {y}^{2} + 2xy$

$= 49$

${x}^{2} + {y}^{2} = 49 - 2 \times 12$

$\bf {{x}^{2} + {y}^{2}= 25}$

Hope it will be helpful :)

Answer 2

Answer:

$given = (x + y) = 7 \\ \: \: \: \: \: xy = 12 \\ to \: find = {x}^{2} + {y}^{2} \\ find = as \: we \: know \: that \: {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{2} + {y}^{2} = {7}^{2} - 2 \times 12 = 49 - 24 = 25$

Hope its help uh..❤