Question

if x+y =8 and x^2+y^2=36 find xy​

Answer 1

Answer:

hop it will help

Step-by-step explanation:

this is the answer to your questio

Answer 2

Step-by-step explanation:

Given

x+ y = 8

${x^{2} + y }^{2} = 36$

FIND:

value of xy

Now ,

x + y = 8

square both side

$(x + y) {}^{2} = {8}^{2}$

${x}^{2} + {y}^{2} + 2xy = 64 ....(1)$

a/c to question

$value \: of \: {x}^{2} + {y}^{2} = 36 \\ \: put \: in \: equation \: (i)$

36 + 2xy = 64

2xy = 64 - 36

2xy = 28

xy = 28/2

xy = 14

hope it helps you