Question

if x+y=8 and x-y=6then find the x and y​

Answer 1

A system of equations in two or more variables can be used to solve the conjugate statement (x^2+y^2)

x-y=6

x-(y-y)=6+y

x-0=6+y

x=

6+y

By substitution, if x=6+y, then xy=8 can be written as:

(6+y)y=8

y^2+6y-8=8–8

y^2+6y-8=0

By the quadratic formula, y^2+6y-8 yields

y=[-6 +/- √6^2–(4)(1)(-8)]/2

y=[-6 +/- √36-(-32)]/2

y=[-6 +/- √36+32]/2y=[-6 +/- √68]/2

y=[-6 +/- √(2^2×17)]/2

y=(-6 +/- 2√17)/2

y=-3 +/- 1√17

y=

-3 +/- √17

CALCULATIONS

Y=x^2+y^2

Y=(6+y)^2+(-3 +/- √17)^2

Y=

y^2+12y+37.261366

Answer 2

Answer:

x=14,y=48

Step-by-step explanation:

please like and follow me