Question

If x+y = 8 and x²+y² = 40, find the value of x and y

Answer 1

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Answer 2

here is ur answer buddy......
x+y=8
x²+y²=40

(x+y)²=64
x²+y²+2xy=64
40+2xy=64
2xy=24
xy=12
x=12/y

x+y=8
(12/y)+y=8
12+y²=8y
y²-8y+12=0
(y-6)(y-2)=0
=>y=6,2

x+y=8
if y=6
x+6=8
x=2

if y=2
x+2=8
x=6

hope it helps....