Question

if x y 8 and xy 12 find the value of (x2+y2)

Answer 1

Step-by-step explanation:

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Answer 2

The value of $x^2+y^2$ = 40

Step-by-step explanation:

The complete question:

If x + y = 8 and xy = 12, find the value of ($x^2+y^2$).

Given,

x + y = 8 and xy = 12

To find, the value of $x^2+y^2$ = ?

∴ x + y = 8

Squaring both sides, we get

$(x+y)^2=8^2$

⇒ $x^{2} +y^{2} +2xy=64$

Put xy = 12, we get

⇒ $x^{2} +y^{2}$ + 2(12) = 64

⇒ $x^{2} +y^{2}$ + 24 = 64

⇒ $x^{2} +y^{2}$ = 64 - 24 = 40

∴ $x^2+y^2$ =  40

Thus, the value of $x^2+y^2$ = 40