Question

If x + y = 8 and xy =15 , find x2 + y2.

Answer 1

x=3
y=5
x2+y2=9+25=34

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Answer 2

Here's your answer!!

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It is given that,

$= > x + y = 8....(1)$
And,

$= > xy = 15.....(2)$

We have to find value of ,

$= > {x}^{2} + {y}^{2}$

We know that,

$= > {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$
So,

$= > {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy$

By substituting value of equation (1)and (2),we get :-


$= > {x}^{2} + {y}^{2} = {(8)}^{2} - 2(15)$

$= > {x}^{2} + {y}^{2} = 64 - 30$

Hence,

$= > {x}^{2} + {y}^{2} = 34$

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Hope it helps you!! :)