If x + y = 8 and xy =15 , find x2 + y2.
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to find x²+y²
applying identity
(x+y)²=x²+y²+2xy
x+y=8 (given),xy=15 (given)
(8)² =x² + y²+2(15)
64=x²+y² +30
64-30=x²+y²
34=x²+y²
applying identity
(x+y)²=x²+y²+2xy
x+y=8 (given),xy=15 (given)
(8)² =x² + y²+2(15)
64=x²+y² +30
64-30=x²+y²
34=x²+y²
Answered by
34
♣ It is given that, ♣
x + y = 8 and xy = 15.
♣ To find ♣
The value of x² + y².
♣ Solution ♣
We know,
x² + y² = (x + y)² - 2xy
⇒x² + y² = (8)² - 2(15)
⇒x² + y² = 64 - 30
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