If x+y= 8 and xy =15 find x3 +y3
Answers
Answered by
53
hey friend
given that .
=)x+y = 8 ----------------(1)
=) xy = 15 ----------------(2)
from equation (1)
=) x+y = 8
cubing both sides
=)( x+y)^3 = 8^3
=) x^3 + y^3 + 3xy(x+y) = 512
=) x^3 + y^3 +3×15×8 = 512
=) x^3 +y^3 +360 = 512
=) x^3 + y^3 = 512 - 360
=) x^3 + y^3 = 152 ans.
____________________________
hope it helps
given that .
=)x+y = 8 ----------------(1)
=) xy = 15 ----------------(2)
from equation (1)
=) x+y = 8
cubing both sides
=)( x+y)^3 = 8^3
=) x^3 + y^3 + 3xy(x+y) = 512
=) x^3 + y^3 +3×15×8 = 512
=) x^3 +y^3 +360 = 512
=) x^3 + y^3 = 512 - 360
=) x^3 + y^3 = 152 ans.
____________________________
hope it helps
arbazkhan:
are you sure this is right ans
Answered by
9
We need 2 numbers whose sum is 8 and product is 15 so we have
3 and 5
So now (3*3)+(5*3)=24
3 and 5
So now (3*3)+(5*3)=24
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