Question

If x + y = 8 and xy = 32, find the values of
(i) x-y
(ii) 3(x2 + y2) (iii) 5(x2 + y2) + 4(x - y).​

Answer 1

Step-by-step explanation:

It is give that X + Y = 8 and xy = 32

And question say to find value of ☓ - Y, 3(X square + Y square) and 5( X Square + Y Square) + 4 (X - Y).

Now we solve this :

(1) 4 - 4 = 0

Now you think why we half this because question say to subtract (➖) so we half this and then we solve this.

(2) 3 (4 square + 4 square)

3 (16 + 16)

3 * 32

= 96

(3) 5 (4 square + 4 Square) + 4 (4 - 4)

5 (16 + 16) + 4 (0)

5 * 32 + 0

160 + 0

= 160

HOPE IT HELPS TO YOU

Answer 2

Step-by-step explanation:

If x + y = 8 and xy = 32, find the values of

(i) x-y

(ii) 3(x2 + y2) (iii) 5(x2 + y2) + 4(x - y).

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