Question

if x + y = 8 and xy = 33, find the values of

5(x2 + y2) + 4(x - y).​

Answer 1

Answer:

$\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}$

$\implies$

= 5[ (x² + y²) + 4(x - y)]

= 5 [(x + y)² - 2xy ] + 4(x - y)]

= 5 [8²-2 × 15/4] + 4 × 7

= 5 [ 64 - 15/2 ] + 28

= 5 x 113/2+28

= 565/2 + 28

= (565 + 56 )/2

= 621/2.

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Answer 2

Step-by-step explanation:

= 5[ (x² + y²) + 4(x - y)]

= 5 [(x + y)² - 2xy ] + 4(x - y)]

= 5 [8²-2 × 15/4] + 4 × 7

= 5 [ 64 - 15/2 ] + 28

= 5 x 113/2+28

= 565/2 + 28

= (565 + 56 )/2

= 621/2.