Question

if x-y=8 and xy=41 then what will me the value of x^3-y^3?​

Answer 1

Answer:

1,496

Step-by-step explanation:

x-y=8

xy=41

find x^3-y^3

therefore,

(x-y)^3=x^3-y^3-3xy(x-y)

(8)^3=x^3-y^3-3(41)(8)

512=x^3-y^3-984

512+984=x^3-y^3

1496=x^3-y^3

Answer 2

Answer:

Step-by-step explanation:

[x+y]^2=[x-y]^2+4xy

[x+y]^2=8^2+4*41= 228

x+y=15.01

x-y=8

2y=7.01

y= 3.505

x=11.505

x^3-y^3=132.365-12.285=120.08