If x-y=8 and xy=5, find x²+y² and x³+y³
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Step-by-step explanation:
The answer is -15
xy=12—equation 1
x+y=3—equation 2
To find: x²+ y²
We know that
(x+y)²=x²+y²+2xy —equation 3
We have in equation 1
=>x+y=3
Squaring both sides
=>(x+y)²=3²
=>(x+y)²=9
So the value of (x+y)² is 9
Secondly, we have in equation 2
=>xy=12
Multiplying 2 in both sides
=>2xy=2×12
=>2xy=24
So the value of 2xy is 24
Now we have the equation 3 that is (x+y)²=x²+y²+2xy, and by substituting the value of (x+y)² and 2xy in equation 3, we can get the value of x²+y²,
=>(x+y)²=x²+y²+2xy
=>9=x²+y²+24
=>9–24=x²+y²
=>x²+y²=-15
So the value of x²+y² is -15
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