Question

: If x+y=8 and xy=5, then find the value of x2+y2.

Answer 1

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If x+y=8 and xy=5, then

find the value of

$x{}^{2} + y {}^{2}$

${\green{\huge{\underline{\mathbb{ Answer:-}}}}}$

$x {}^{2} + y {}^{2}$

$= (x + y) {}^{2} - 2xy$

put the given values

x+ y =8 and xy = 5

__________________________

$= (8) {}^{2} - 2(5)$

$= 64 - 10$

$= 54$

Answer 2

Answer:

(x+y)^2 = x^2 + y^2 + 2xy

(8)^2 = x^2 + y^2 +2*5

64 = x^2 + y^2 + 10

x^2 + y^2 = 54