Question

If x+y=8 and xy=6, then x3 + y3 =

Answer 1

Answer:

368

Step-by-step explanation:

x³+y³ = (x+y)(x²-xy+y²)

=8(x²+y²-6) [add and subtract 2xy]

=8(x²+y²+2xy-2xy-6)

=8[(x+y)²-2xy-6]

=8[(8)²-2(6)-6]

=8(64-12-6)

=8(46)

=368

I hope by X3+y3 you mean x³+y³

Answer 2

Answer:

answer is 368

Step-by-step explanation:

x³+y³ = (x+y)(x²-xy+y²)

=8(x²+y²-6) [add and subtract 2xy]

=8(x²+y²+2xy-2xy-6)

=8[(x+y)²-2xy-6]

=8[(8)²-2(6)-6]

=8(64-12-6)

=8(46)

=368