Question

If x+y=8andxy=15,then x²+y²​

Answer 1

Simple values are not so big use hit nd trial first multiple of 15 u simply get 15*1 or 5*3 use it get ur answer

Answer 2

GIVEN:

x+y=8

xy=15

TO FIND:x²+y²

SOLUTION:

(x+y)²=x²+y²+2xy

(8)²=x²+y²+2*15

64=x²+y²+30

64-30=x²+y²

34=x²+y²

SO REQUIRED VALUE OF  x²+y²=34

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