If x+y=8andxy=15,then x²+y²
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Simple values are not so big use hit nd trial first multiple of 15 u simply get 15*1 or 5*3 use it get ur answer
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GIVEN:
x+y=8
xy=15
TO FIND:x²+y²
SOLUTION:
(x+y)²=x²+y²+2xy
(8)²=x²+y²+2*15
64=x²+y²+30
64-30=x²+y²
34=x²+y²
SO REQUIRED VALUE OF x²+y²=34
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