Question

If x + y = 9 and xy = 14, find x^2-y^2.

Answer 1

Answer:

is this question right.

Answer 2

$given \: x + y = 9 \: \: and \: \: xy = 14 \\ = > \: so \: possible \: numbers \: who \: has \: multiple \: of \: 14 \: are: \\ 1 \times 14 = 14 \\ 2 \times 7 = 14 \\ now \: from \: the \: sets \: we \: can \: clearly \: see \: that \: \\ 7 + 2 = 9 \: \: and \: \: 7 \times 2 = 14 \\ = > \: x = 7 \: or \: 2 \: \: and \: y = 7 \: or \: 2 \\ if \: x = 7 \: and \: y = 2 \: then \\ = > {x}^{2} - {y}^{2} \\ = > {7}^{2} - {2}^{2} \\ = > 49 - 4 = 45 \\ also \: if \: x = 2 \: and \: y = 7 \: then \\ = > {x}^{2} - {y}^{2} \\ = > {2}^{2} - {7}^{2} \\ = > 4 - 49 = ( - 45) \\ so \: possible \: value \: of \: {x}^{2} - {y}^{2} \: is \: 45 \: or \: ( - 45)$

Hope it helps you

Please mark me as a brainliest !!!!