Question

If x+y=9 and xy=16 ,find the value of (x square +y sqaure

Answer 1

Answer:

17

Step-by-step explanation:

${( x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ = > {9}^{2} = {x}^{2} + {y}^{2} + (2 \times 16) \\ = > {x}^{2} + {y}^{2} = 81 - 32 = 49$