if x+y=9 and xy=16, find the value of (x²+y²)
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Answered by
5
Answer:
49
Step-by-step explanation:
(x+y)^2=x^2+y^2+2xy
(9)^2=x^2+y^2+2*16
81-32=x^2+y^2
49=x^2+y^2
hope it helps
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1
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