Math, asked by sanskriti194, 1 year ago

if x+y=9 and xy=16 ...find the value of (x2 + y2 ) ​

Answers

Answered by Anonymous
81

Answer:

Step-by-step explanation:

(x+y)^2=x^2+y^2+2xy

(9)^2=x^2+y^2+2*16

81-32=x^2+y^2

49=x^2+y^2

.hope it helps u!!!!

Answered by sachin3183
102

(x + y)2=x2 + y2 + 2 xy

81=x2 + y2 + 2×16

x2 + y2 = 81-32

=49

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