if x+y=9 and xy=16 ...find the value of (x2 + y2 )
Answers
Answered by
81
Answer:
Step-by-step explanation:
(x+y)^2=x^2+y^2+2xy
(9)^2=x^2+y^2+2*16
81-32=x^2+y^2
49=x^2+y^2
.hope it helps u!!!!
Answered by
102
(x + y)2=x2 + y2 + 2 xy
81=x2 + y2 + 2×16
x2 + y2 = 81-32
=49
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