if x+y =9 and xy = 18,find the value of x^3 +y^3
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Answers
Answered by
1
Answer:
Correct option is
C
189
We know that
x
3
+y
3
=(x+y)
3
−3xy(x+y)
so, x
3
+y
3
=(3)
3
−3(−18)(3)
=27+162
x
3
+y
3
=189
Answered by
3
Answer:
(x+y)^3 =x^3+y^3+3xy(x+y)
(9)^3= x^3+y^3+3(18)(9)
729= x^3+y^3+486
x^3+y^3= 729- 486
x^3+y^3=243
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