Question

If x+y=9 and xy=20 find x-y

Answer 1

Answer:

+-1

Step-by-step explanation:

(x-y)2 = (x+y)2 - 4xy

=81 - 4*20

= 1

x-y =√1

+-1

Answer 2

Answer :-

The value of (x - y) is √1 respectively.

Solution :-

Given :

x + y = 9

xy = 20

We know that,

${(x + y)}^{2} = {(x - y)}^{2} + 4xy$

Putting the values,

$= > {9}^{2} = {(x - y)}^{2} + 4 \times 20$

$= > 81 = {(x - y)}^{2} + 80$

$= > 81 - 80 = {(x - y)}^{2}$

$= > 1 = {(x - y)}^{2}$

$= > {(x - y)}^{2} = 1$

$= > (x - y) = \sqrt{1}$

Hence, the value of (x - y) is √1.