Question

If x+ y = 9 and xy = 5 find the value of x2 + y2.​

Answer 1

Step-by-step explanation:

Given, x+y=9 and xy=16.

Given, x+y=9 and xy=16.We know, (a+b)

Given, x+y=9 and xy=16.We know, (a+b) 2

Given, x+y=9 and xy=16.We know, (a+b) 2 =a

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .Then,

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .Then,(x+y)²=x²+2xy+y²

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .Then,(x+y)²=x²+2xy+y²⟹ (9)²=x²+2(16)+y²

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .Then,(x+y)²=x²+2xy+y²⟹ (9)²=x²+2(16)+y²⟹ 81=x²+32+y²

Given, x+y=9 and xy=16.We know, (a+b) 2 =a 2 +2ab+b 2 .Then,(x+y)²=x²+2xy+y²⟹ (9)²=x²+2(16)+y²⟹ 81=x²+32+y²⟹ x²+y²=81−32=49.

Answer 2

Step-by-step explanation:

49 is the correct answer

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