Math, asked by veereshmu, 4 months ago

If x – y = 9, xy = 16, then find the value of x^2 + y^2

Answers

Answered by rishabh1542
2

Answer:

here is your answer

Step-by-step explanation:

by using (x-y)^2 = x^2 - 2xy + y^2

(9)^2= x^2 + y^2 - 2*16

81-32=x^2 + y^2

49=x^2 + y

Answered by pritikasil2004
2

Answer:

If x – y = 9, xy = 16, then find the value of x^2 + y^2

If x+y=9 , xy=16

Now- x^2+y^2

= (x +y)^2 - 2xy

= (9)^2 - 2xy

= 81 -2 × 16

= 81 - 32

= 49

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