Question

If x+y=9 xy=20 the find (x-y)​

Answer 1

Answer:

The value of (x - y) is √1 respectively.

Solution :-

Given :

x + y = 9

xy = 20

We know that,

{(x + y)}^{2} = {(x - y)}^{2} + 4xy(x+y)

2

=(x−y) 2 +4xy

Putting the values,

= > {9}^{2} = {(x - y)}^{2} + 4 \times 20=>9 2

=(x−y) 2 +4×20

= > 81 = {(x - y)}^{2} + 80=>81=(x−y)

2

+80

= > 81 - 80 = {(x - y)}^{2}=>81−80=(x−y)

2

= > 1 = {(x - y)}^{2}=>1=(x−y)

2

= > {(x - y)}^{2} = 1=>(x−y)

2

=1

= > (x - y) = \sqrt{1}=>(x−y)=

1

Hence, the value of (x - y) is √1.