Math, asked by raghubir041978, 5 months ago

if x-y=9and xy=16 find the value of x2+y2​

Answers

Answered by abdurrafay102003
0

Answer:

49

Step-by-step explanation:

We have, x+y=9 and xy=16

(x+y)²=x²+2xy+y²=81

x²+y²=81−2xy=81−2(16)=81−32=49

Answered by arijitduttachowdhury
5

Step-by-step explanation:

Given, x-y = 9, xy = 16

By condition,

(x-y)² = x²-2xy+y²

x²-(2×16)+y² = (9)²

x²-32+y² = 81

x²+y² = 81+32

x²+y² = 113

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