if x+y = a and x2+y2 = b then find the value of x3+y3
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Step-by-step explanation
x +y = a
square on both sides
you will get
x² + y² + 2xy = a²
b + 2xy = a²
2xy = a² - b
xy = a² -b /2
cube the same equation and you will get
(x+y)³ = a³
x³ + y³ + 3xy (x+y) = a³
x³ +y³ + 3 (a² -b /2) (a ) = a³
x³ +y³ + 3 ( a³ - ab /2) = a³
x³+y³ + (3a³ - 3ab) /2 = a³
multiply the whole equation by 2
2x³ +2y³ +3a³ - 3ab = 2a³
2(x³ + y³) = 2a³ - 3a³ + 3ab
2(x³ +y³) = 3ab - a³
x³ + y³ = 3ab-a³ /2
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