Math, asked by uditsolanki13, 1 month ago

If x+y=a; xy=b^2; Find x^3-x^2y-xy^2+y^3=?

Answers

Answered by sjain05040710
0

Answer:

1

+

y

3

1

=

x

3

y

3

x

3

+y

3

=

(xy)

3

(x+y)

3

−3xy(x+y)

=

b

3

a

3

−3ba

=

b

3

a

3

−3ab

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