Question

if X+y =⅖ and XY = 1, find x-y ​

Answer 1

Answer:

OK maths hero give u answer it is me

Step-by-step explanation:

y∣=x−1

since ∣y∣ is always positive

x−1 will always be a positive number

That means x is always greater than equal to 1

so now the equations become

x+2+y=5...(1)

x−y=1...(2)

solving (1) and (2) we get,

x=2 and y=1

⇒x+y=2+1=3

Answer 2

Answer:

Step-by-step explanation:

x+y=2/5

xy=1

now,

(x^2+y^2)=(x-y)^2+2.xy[∵a^2+b^2=(a+b)^2 - 2.a.b  or (a-b)^2 + 2.a.b]

(x+y)^2-2.xy=(x-y)^2+2.xy

(2/5)^2 - 2*1 = (x-y)^2+2*1

4/25-2=(x-y)^2+2

4/25-2-2=(x-y)^2

4/25-4=(x-y)^2

-96/25=(x-y)^2

-3.84=(x-y)^2

x-y=1.95..........