If x=-y and y>0, which of the following is wrong?
a) x^2y>0
b) x+y = 0
c) xy<0
d) 1/x - 1/y = 0
Answers
Given: The value of x = -y and y > 0.
To find: Which of the following is wrong?
a) x^2y>0
b) x+y = 0
c) xy<0
d) 1/x - 1/y = 0
Solution:
- Now we have given the value of x as -y, so putting them in all four options, we get:
a) x² y > 0
(-y)²y > 0
y²y > 0
y³ > 0 ......True as cube of positive number is always greater than 0.
b) x+y = 0
(-y) + y = 0
0 = 0 ........True
c) xy<0
(-y)y < 0
-y² < 0 True as the final answer is having negative sign.
d) 1/x - 1/y = 0
-1/y - 1/y = 0
-2/y ≠ 0 False as the final answer is not 0.
- So 4 th option is wrong.
Answer:
So among the four options, the fourth option 1/x - 1/y = 0 is wrong.
Answer:
yes, the fourth option is wrong
1/x - 1/y = 0