if X, Y and Z are in proportion, find y if X = 8 and Z = 32.
Answers
Answered by
33
HERE YOU GO WITH YOUR SOLUTION:
X/Y=Y/Z
8/Y=Y/32
Y^2=8×32
Y^2=256
Y=√256
Y=16
HOPE IT HELPS
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X/Y=Y/Z
8/Y=Y/32
Y^2=8×32
Y^2=256
Y=√256
Y=16
HOPE IT HELPS
PLEASE MARK AS BRAINLIEST
Answered by
2
Answer:
y = 16
Step-by-step explanation:
if x, y, z are in proportion then,
=> x/y = y/z
=> 8/y = y/32
=> y^2 = 8 x 32
=> y = √256
=> y = 16
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