Question

if x, y are real no. and (x-a)2 +(x-y) 2 =0.what are the value of x, y​

Answer 1

Answer:

65

Step-by-step explanation:

Real Numbers

The Real Numbers had no name before Imaginary Numbers were thought of. They got called "Real" because they were not Imaginary.

Means X and Y can be any number but not imaginary.

(x - 1)^2 + (y - 4)^2 = 0

first solution who satisfy this condition:

(x - 1)^2 =0 , x=1 ; (y - 4)^2=0 ,y=4; x^3 + y^3 = 1+64=65

then finding another solution :

(x - 1)^2 =1,1+-sqrt(1) then must be fitting this condition (y - 4)^2=-1 , it gives imaginary number where for our Y is real number so not satisfy this condition.

So only one solution are there and That is 65.