if x,y are real number and (x-5)^2+(x-y)^2=0.what is the value of x and y
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as there is (x-5)² + (x-y)² = 0
so , we can say that (x-5)² =0
then we can say (x-5)=0
so. x=5
and (x-y)² =0
then we can say (x-y)=0
so. x=y=5
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