Question

if x,y are roots of ax²+bx+c then find 1/x²+1/y²​

Answer 1

Answer:

uajqhwiasvvwh1i2bwvshsjs ebsudbbdjss

sjhwvehdjw

Answer 2

Answer:

prefer to it child!!

it's similar to it only...

Step-by-step explanation:

Since x,y roots of

X2−6xy−91y2=0

on factorization and solving we get:

X2−13xy+7xy−91y2=0

X(x−13y)+7y(x−13y)=0

(X-13y)(x+7y)=0

Now we get: x=13y and x=-7y .

(0,0) is the common value satisfying both equations .hence x2+y2 is 0.