If x – y = c, z – x = b, y – z = a, a2 + b2 + c2 =25, then the value of x2 + y2 + z2– xy – yz – zx is equal to
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11
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To find:-
x² + y² + z²– xy – yz – zx
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Given:-
x – y = c, z – x = b, y – z = a
a²+b²+c²=25
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a² + b²+ c² = 25
(y – z)² + (z – x)² + (x – y)² = 25
y² + z² -2yz + z² + x² -2zx x² + y² -2xy = 25
2x² +2y² + 2z² - 2xy -2yz -2zx = 25
2(x² +y² + z² - xy - yz - zx) = 25
x² +y² + z² - xy - yz - zx = 25/2
x² +y² + z² - xy - yz - zx = 12.5
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x² +y² + z² - xy - yz - zx = 12.5
Answered by
10
Hello,
- a²+b²+c²=25
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➥a² + b²+ c² = 25
➥(y – z)² + (z – x)² + (x – y)² = 25
➥y² + z² -2yz + z² + x² -2zx x² + y² -2xy = 25
➥2x² +2y² + 2z² - 2xy -2yz -2zx = 25
➥2(x² +y² + z² - xy - yz - zx) = 25
➥x² +y² + z² - xy - yz - zx = 25/2
➥x² +y² + z² - xy - yz - zx = 12.5 ..
Hope it helps uh !
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