If x^y denotes x raised to the power y,then find last two digit of 1507^3381+1457^3757
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Answer:
The last two digits are 64.
Explanation:
The given problem can be reduced to finding the last 2 digits.
Note that 57² ≡ 7² ≡ 49(mod100),
so that 57⁴ ≡ 7⁴ ≡ 49² ≡ 1(mod100).
Therefore,
1507³³⁸¹+1457^³⁷⁵⁷
= 7³³⁸¹ + 57³⁷⁵⁷ (mod 100)
= 7*(7⁴)⁸⁴⁵ + 57*(57⁴)⁹³⁹ (mod 100)
= 7 (1) + 57 (1)
= 7 + 57
= 64 last two digits
That's the final answer.
I hope its help you.
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