Question

If x,y E R and (x + iy) (3 + 2i) = 1+i, then (x,y) is​

Answer 1

Answer:

x=15/13&y=1/13

Step-by-step explanation:

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Answer 2

Another method

(x+iy)(3+2i) = 1+i

x+iy = (1+I)/(3+2i)

rationalising RHS with (3-2i) we get

x+iy = (1+I)(3-2i)/(3+2i)(3-2i)

x+iy = (3-2i+3i - 2i^2)/(3^2 - (2i)°2)

x+iy = (3+i+2)/(9+4)

x+iy = (5+I)/13

x+iy = 5/13 + (1/13)i

on comparison,

x = 5/13, y = 1/13