Question

If X + y equal 2, then find the value of x cube + 6 X y + y cube minus 8

Answer 1

Answer:

here is the answer. I hope you understand.

Answer 2

The required value is 0.

Step-by-step explanation:

Since we have given that

$x+y=2$

We need to find the value of $x^3+6xy+y^3-8$

So, if we cubing the above equation, we get that

$(x+y)^3=2^3\\\\x^3+y^3+3xy(x+y)=8\\\\x^3+y^3+3xy\times 2=8\\\\x^3+y^3+6xy-8=0$

Hence, the required value is 0.

# learn more:

If 3 x minus 2 Y is equal to 5 and X Y is equal to 6 find the value of 27 x cube minus 8 y cube

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