Question

If x + y equal to 12 and x y equal to 32, find the value ofx^2
+ y^2

Answer 1

Answer:

80

Step-by-step explanation:

(x+y) ^2 = x^2+y^2+2xy

PUTTING THE GIVEN VALUES,

(12)^2 = x^2+y^2+2*32

144 = x^2+y^2+64

144-64 = x^2+y^2

x^2+y^2 = 80

PLEASE MARK IT AS BRAINLIEST.

Answer 2

Mark As Brainliest

Here is your answer >>

Given : x+y=12 , xy=32

Find : x^2+y^2

Solution :

x+y=12

so now square both sides

(x+y)^2 = (12)^2

x^2 + y^2 + 2xy = 144

$x ^{2} + y^{2} = 144 - 2xy$

So,

$x^{2} + y^{2} = = 80$

I hope this will help you.