Question

If X + Y equal to 8 and X *Z equal to 21 and Y minus w equal to 5 and Z * w equal to 9 then find the numbers

Answer 1

Given: The equations x + y = 8, xz = 21, y - w = 5 and zw = 9

To find: the numbers.

Solution:

• Now we have given the equations:

                 x + y = 8  ...............(i)

                 xz = 21     ...............(ii)

                 y - w = 5  ...............(iii)

                 zw = 9     ...............(iv)

• From (i) and (iii), we get:

                 y = 8 - x and y = 5 + w

• It implies:

                 8 - x = 5 + w

                 w = 3 - x  ...............(v)

• Putting (v) in (iv), we get:

                 z(3 - x) = 9

                 3z - zx = 9

• Putting (ii), we get:

                 3z - 21 = 9

                 3z = 30

                 z = 10

• Putting z in ii, we get:

                 x = 21/10 = 2.1

• Putting z in iv, we get:

                 w = 9/10 = 0.9

• Putting w in iii, we get:

                 y - 0.9 = 5

                 y = 5.9

Answer:

            So the values are: x = 2.1, y = 5.9, z = 10 and w = 0.9

Answer 2

Answer:

X=

Y=

zz=

Step-by-step explanation: