Question

if x-y is 24, xy is 38, then find x^2+y^2​

Answer 1

Step-by-step explanation:

given ,x-y=24 so x=24+y

and given xy=38 ( eq 1)

substitute value of x in eq 1

so,(24+y)y=38

24y+y^2=38

y^2+24y-38=0

y^2+2y-19y-38=0

y(y+2)-19(y+2)=0

so y=-2 or y=19

so it camt be negative so let's take the value of y as 19

and then substitute value of y in x=24+y

so x=24+19=43

therefore x^2+y^2=(43)^2+(19)^2

=1849+361

=2210

but given in question xy=38 check it out pls ....it's not 38 it's (19)(43)=817