If x + y is 6 and 2x + 3 y is 12 find the value of x & y?
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Answer:
value of x and y are 6 and 0 respectively
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Given: x + y = 6 and 2x + 3y = 12.
To find: The value of x and y.
Answer:
Let x + y = 6 be equation 1 and 2x + 3y = 12 be equation 2.
From equation 1,
x = 6 - y
Substituting the above value in equation 2,
2(6 - y) + 3y = 12
12 - 2y + 3y = 12
-y = 12 - 12
y = 0.
Substituting the above value in equation 1,
x + 0 = 6
x = 6
Verification:
Equation 1:
LHS: x + y
RHS: 6
Using the values of x and y in LHS,
6 + 0 = 6
LHS = RHS
Equation 2:
LHS: 2x + 3y
RHS: 12
Using the values of x and y in LHS,
2*6 + 3*0 = 12 + 0 = 12
LHS = RHS
Therefore, x = 6 and y = 0.
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