if (x+y) is a factor of the polynomials x square +p x+q and x square +mx+n then prove that a =n-q/m-p
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Step-by-step explanation:
(-a)² + p(-a) + q = 0 --> a² -ap + q = 0
(-a)² + m(-a) + n = 0 --> a² -am + n = 0
Since they both equal 0, you can set them equal to each other:
a² -ap + q = a² -am + n
-ap + q + -am + n
am - ap = n-q
a(m-p) = n-q
or a=n-q/m-p
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