Question

If (x,y) is a point equidistant from the points (7,5) and (4,3) then show that

6x+4y=49.​

Answer 1

Step-by-step explanation:

LetA(x,y),B(7,5) and C(4,3)

AB²=AC²

(x-7)²+(y-5)²=(x-4)²+(y-3)²

x²+49-14x+y²-10y+25=x²+16-8x+y²-6y+9

-14x-10y+74=-8x-6y+25

-14x+8y-10y+6y=25-74

-6x-4y=-49

6x+4y=49 Hence proved

Answer 2

as in the question its mentioned that the points are equidistant zo

AP=BP..using distance formula ..we do the further solving as shown in the pic above..