Question

if x, y is a point on the circumference of the circle whose centre is 3, - 2 and radius 3 unit prove that x square + y square is equal to 6x -4y-4



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Answer 1

$\textbf{Given:}$

$\text{Centre,(h,k)=(3,-2)}$

$\text{Radius, r=3 units}$

$\text{Equation of the required circle is}$

$(x-h)^2+(y-k)^2=r^2$

$\implies\;(x-3)^2+(y+2)^2=9$

$\text{using}$

$\boxed{\bf(a+b)^2=a^2+b^2+2ab}$

$\boxed{\bf(a-b)^2=a^2+b^2-2ab}$

$\implies\;x^2+9-6x+y^2+4+4y=9$

$\implies\;x^2+y^2-6x+4y+4=0$

$\implies\boxed{\bf\;x^2+y^2=6x-4y-4}$

Answer 2

Answer:

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