if x=y is a tangent to curve y=x²+bx+c at(1,1) then b+c=
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Step-by-step explanation:
here given that ( 1 , 1)
therefore
x = 1 , y = 1
hence the equation becomes
1 = ( 1 × 1 ) + (1 × b ) + c
1 = 1 + b + c
1 - 1 = b + c
0 = b + c
answer is b+c = 0
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