If x -y is equal to 13 and X y is equal to - 5 then find the value of 1 / 3 X square + y square
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x-y=13. (1)
xy=-5. (2)
Find
1/3(x^2+y^2)=? (3)
Taking square on both side of eq1
(x-y)^2=13^2
x^2+y^2 - 2xy=169
x^2+ y^2 - 2(-5)=169. xy=-5
x^2+y^2+10=169
x^2+y^2=169-10
x^2+y2=159
Put it in eq3
1/3(159)=53
So
1/3(x^2+y^2)=53
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