if x -y is equals to 4 and x y is equals to 21 find x cube - y cube
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Given
x - y = 4
and xy = 21
x - y = 4
=> (x - y)² = (4)²
=> x² + y² - 2xy = 16
=> x² + y² - 2(21) = 16
=> x² + y² - 42 = 16
=> x² + y² = 58
Now x³ - y³ = (x - y)(x² + y² + xy)
=> x³ - y³ = (4)(58 + 21)
=> x³ - y³ = (4)(79)
=> x³ - y³ = 316
Hope it helps dear friend ☺️✌️
x - y = 4
and xy = 21
x - y = 4
=> (x - y)² = (4)²
=> x² + y² - 2xy = 16
=> x² + y² - 2(21) = 16
=> x² + y² - 42 = 16
=> x² + y² = 58
Now x³ - y³ = (x - y)(x² + y² + xy)
=> x³ - y³ = (4)(58 + 21)
=> x³ - y³ = (4)(79)
=> x³ - y³ = 316
Hope it helps dear friend ☺️✌️
sprao534:
they are asking x cube-y cube
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